unique numbers in array

1var arr = [55, 44, 65,1,2,3,3,34,5];
2var unique = [...new Set(arr)]
3
4//just  var unique = new Set(arr) wont be an array

1let uniqueItems = [...new Set(items)]
2

1import java.util.Random;
2
3public class GenRandArray {
4    //Recommend reseeding within methods
5    static Random rand = new Random();
6
7    public static void fillInt( int[] fillArray ) {
8        //seeds the random for a new random each method call
9        rand.setSeed(System.currentTimeMillis());
10		
11        for(int i = 0; i < fillArray.length; i++)
12        {
13            fillArray[i]= rand.nextInt();
14            
15          	/* for loop to check to make sure that none of the previous
16               numbers added are the same as the one just added. */
17            for (int j = 0; j < i; j++)
18            {
19              	/* if so we need to redo the last random number by
20              	   moving i back one index to be re-set */
21                if (fillArray[i] == fillArray[j])
22                {
23                    i--;
24                }
25            }
26        }
27    }
28}

1import java.util.ArrayList;
2
3public class UniqueNumbersInArray {
4
5    public static void main(String[] args) {
6
7
8    int arr[] = { 4,5,5,4,5,6,5,8,4,7};
9
10        ArrayList<Integer> uniqueArr = new ArrayList<Integer>();
11        for (int i = 0; i < arr.length; i++) {
12
13            int k = 0;
14            if (!uniqueArr.contains(arr[i])){
15                uniqueArr.add(arr[i]);
16                k++;
17
18                for (int j = i; j < args.length ; j++) {
19                    if (arr[i]==arr[j]){
20                        k++;
21                    }
22                }
23
24                System.out.println(arr[i]);
25                System.out.println(k);
26            }
27
28        }
29    }
30}