get an array with unique values

1var arr = [55, 44, 65,1,2,3,3,34,5];
2var unique = [...new Set(arr)]
3
4//just  var unique = new Set(arr) wont be an array

1let a = ["1", "1", "2", "3", "3", "1"];
2let unique = a.filter((item, i, ar) => ar.indexOf(item) === i);
3console.log(unique);

1// usage example:
2var myArray = ['a', 1, 'a', 2, '1'];
3var unique = myArray.filter((v, i, a) => a.indexOf(v) === i); 
4
5// unique is ['a', 1, 2, '1']

1function onlyUnique(value, index, self) {
2  return self.indexOf(value) === index;
3}
4
5// usage example:
6var a = ['a', 1, 'a', 2, '1'];
7var unique = a.filter(onlyUnique);
8
9console.log(unique); // ['a', 1, 2, '1']

1import java.util.Random;
2
3public class GenRandArray {
4    //Recommend reseeding within methods
5    static Random rand = new Random();
6
7    public static void fillInt( int[] fillArray ) {
8        //seeds the random for a new random each method call
9        rand.setSeed(System.currentTimeMillis());
10		
11        for(int i = 0; i < fillArray.length; i++)
12        {
13            fillArray[i]= rand.nextInt();
14            
15          	/* for loop to check to make sure that none of the previous
16               numbers added are the same as the one just added. */
17            for (int j = 0; j < i; j++)
18            {
19              	/* if so we need to redo the last random number by
20              	   moving i back one index to be re-set */
21                if (fillArray[i] == fillArray[j])
22                {
23                    i--;
24                }
25            }
26        }
27    }
28}