sum of an array

1[1, 2, 3, 4].reduce((a, b) => a + b, 0)
2
3// Output: 10

1console.log(
2  [1, 2, 3, 4].reduce((a, b) => a + b, 0)
3)
4console.log(
5  [].reduce((a, b) => a + b, 0)
6)

1const sum = arr => arr.reduce((a, b) => a + b, 0);

1var numbers = [10, 20, 30, 40] 
2var sum = 0;
3for (var i = 0; i < numbers.length; i++) {  sum += numbers[i]}

1/**
2 * C program to find sum of all elements of array
3 */
4
5#include <stdio.h>
6#define MAX_SIZE 100
7
8int main()
9{
10    int arr[MAX_SIZE];
11    int i, n, sum=0;
12
13    /* Input size of the array */
14    printf("Enter size of the array: ");
15    scanf("%d", &n);
16
17    /* Input elements in array */
18    printf("Enter %d elements in the array: ", n);
19    for(i=0; i<n; i++)
20    {
21        scanf("%d", &arr[i]);
22
23        // Add each array element to sum
24        sum += arr[i];
25    }
26
27    printf("Sum of all elements of array = %d", sum);
28
29    return 0;
30}

1const sum = (...args) => args.reduce((a, b) => a + b, 0);
2console.log(sum(1,2,3)); // returns 6