sum of all elements in array javascript

1[1, 2, 3, 4].reduce((a, b) => a + b, 0)
2
3// Output: 10

1console.log(
2  [1, 2, 3, 4].reduce((a, b) => a + b, 0)
3)
4console.log(
5  [].reduce((a, b) => a + b, 0)
6)

1const arrSum = arr => arr.reduce((a,b) => a + b, 0)

1var numbers = [3, 5, 7, 2];
2var sum = numbers.reduce((x, y) => x + y);
3console.log(sum); // returns 17
4
5// other way
6
7x = sumAll(1, 123, 500, 115, 44, 88);
8
9function sumAll() {
10  var i;
11  var sum = 0;
12  for (i = 0; i < arguments.length; i++) {
13    sum += arguments[i];
14  }
15  return sum;
16}

1arrSum = function(arr){  return arr.reduce(function(a,b){    return a + b  }, 0);}

1arr.reduce((a, b) => a + b)