sort list python

1my_list = [9, 3, 1, 5, 88, 22, 99]
2
3# sort in decreasing order
4my_list = sorted(my_list, reverse=True) 
5print(my_list)
6
7# sort in increasing order
8my_list = sorted(my_list, reverse=False) 
9print(my_list)
10
11# another way to sort using built-in methods
12my_list.sort(reverse=True)  
13print(my_list)
14
15# sort again using slice indexes
16print(my_list[::-1])
17
18# Output
19# [99, 88, 22, 9, 5, 3, 1]
20# [1, 3, 5, 9, 22, 88, 99]
21# [99, 88, 22, 9, 5, 3, 1]
22# [1, 3, 5, 9, 22, 88, 99]

1# defning A as a list
2A.sort(reverse = True)

1sorted(iterable, key=None, reverse=False)
2
3type(sorted(iterable, key=None, reverse=False)) = list

1a_list = [3,2,1]
2a_list.sort()

1>>> a = [5, 2, 3, 1, 4]
2>>> a.sort()
3>>> a
4[1, 2, 3, 4, 5]
5

1>>> student_tuples = [
2...     ('john', 'A', 15),
3...     ('jane', 'B', 12),
4...     ('dave', 'B', 10),
5... ]
6>>> sorted(student_tuples, key=lambda student: student[2])   # sort by age
7[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]
8