sort dict of dicts by key

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Emmalyn
03 Jan 2020
1channels = {
2'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'}, 
3'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'}, 
4'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'}, 
5'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'}, 
6'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'}, 
7'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'}, 
8'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
9}
10
11channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
12for key,value in channels.items():
13    print(key, ':', value)
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