1s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
2k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
3print(k)
1x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
2{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
3{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
1orders = {
2 'cappuccino': 54,
3 'latte': 56,
4 'espresso': 72,
5 'americano': 48,
6 'cortado': 41
7}
8
9sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)
10
11for i in sort_orders:
12 print(i[0], i[1])