how to sort dictionary in python by value

1s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
2k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
3print(k)

1x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
2
3sort_by_key = dict(sorted(x.items(),key=lambda item:item[0]))
4sort_by_value = dict(sorted(x.items(), key=lambda item: item[1]))
5
6print("sort_by_key:", sort_by_key)
7print("sort_by_value:", sort_by_value)
8
9# sort_by_key: {0: 0, 1: 2, 2: 1, 3: 4, 4: 3}
10# sort_by_value: {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

1import operator
2x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
3sorted_x = sorted(x.items(), key=operator.itemgetter(1))
4
5
6# Sort by key
7import operator
8x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
9sorted_x = sorted(x.items(), key=operator.itemgetter(0))
10

1>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
2>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
3{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
4

1sorted(A, key=A.get)

1# your dictionary
2a = {'a':4, 'c':5, 'b':3, 'd':0}
3
4# sort x by keys
5a_keys = dict(sorted(a.items(),key=lambda x:x[0],reverse = False)) # ascending order
6# output: {'a': 4, 'b': 3, 'c': 5, 'd': 0}
7
8# # sort x by values
9a_values = dict(sorted(a.items(),key=lambda x:x[1],reverse = False)) # ascending order
10# output: {'d': 0, 'b': 3, 'a': 4, 'c': 5}