max in array java

1 // Initializing array of integers 
2        Integer[] num = { 2, 4, 7, 5, 9 }; 
3// using Collections.min() to find minimum element 
4        // using only 1 line. 
5        int min = Collections.min(Arrays.asList(num)); 
6  
7        // using Collections.max() to find maximum element 
8        // using only 1 line. 
9        int max = Collections.max(Arrays.asList(num)); 

1public static double max(double[] arr) {
2  double result = arr[0];
3  for (int i = 1; i < arr.length; ++i) {
4    if (result < arr[i]) result = arr[i];
5  }
6  return result;
7}

1public static String max(String[] arr) {
2  String result = arr[0];
3  for (int i = 1; i < arr.length; ++i) {
4    if (result.compareTo(arr[i]) < 0) result = arr[i];
5  }
6  return result;
7}

1public static double arrayMax(double[] arr) {
2    double max = Double.NEGATIVE_INFINITY;
3
4    for(double cur: arr)
5        max = Math.max(max, cur);
6
7    return max;
8}

1public static double max(double[] arr) {
2  double result = Double.NEGATIVE_INFINITY;
3  for (int i = 0; i < arr.length; ++i) {
4    if (result < arr[i]) result = arr[i];
5  }
6  return result;
7}

1Integer[] num = { 2, 4, 7, 5, 9 };
2        // using Collections.min() to find minimum element
3        // using only 1 line.
4        int min1 = Collections.min(Arrays.asList(num));
5
6        // using Collections.max() to find maximum element
7        // using only 1 line.
8        int max1 = Collections.max(Arrays.asList(num));
9        System.out.println(min1); // 2 
10        System.out.println(max1); // 9