find maximum number in java

1int[] arr = {2, 3, 4, 5, 6, 7, 8, 9,};
2        int max = arr[0]; // max tanimliyorsun
3        int min = arr[0];  // min tanimliyorsun
4
5        for (int i = 0; i < arr.length; i++) {
6            if (arr[i] > max){ 
7// array's index are compared with each other,
8// whichever is greater will be assigned to max
9                max = arr[i];
10            }
11            if(arr[i] < min){ 
12//array's index are compared with each other,
13// whichever is smaller will be assigned to min
14                min = arr[i];
15            }
16        }
17        System.out.println(max); // 9
18        System.out.println(min);  // 2

1        int[] arr = {2, 3, 4, 5, 6, 7, 8, 9,};
2        int max = arr[0]; // max tanimliyorsun
3        int min = arr[0];  // min tanimliyorsun
4
5        for (int i = 0; i < arr.length; i++) {
6            if (arr[i] > max){ 
7// array's index are compared with each other,
8// whichever is greater will be assigned to max
9                max = arr[i];
10            }
11            if(arr[i] < min){ 
12//array's index are compared with each other,
13// whichever is smaller will be assigned to min
14                min = arr[i];
15            }
16        }
17        System.out.println(max); // 9
18        System.out.println(min);  // 2