max element in dictionary python

1dic={0: 1.4984074067880424, 1: 1.0984074067880423, 2: 1.8984074067880425, 3: 2.2984074067880425, 4: 2.2984074067880425}
2max_value = max(dic.values())  # maximum value
3max_keys = [k for k, v in dic.items() if v == max_value] # getting all keys containing the `maximum`
4
5print(max_value, max_keys)

1my_dict = {'a': 5, 'b': 10, 'c': 6, 'd': 12, 'e': 7}
2max(my_dict, key=my_dict.get) # returns 'd'

1import operator
2stats = {'a':1000, 'b':3000, 'c': 100}
3max(stats.iteritems(), key=operator.itemgetter(1))[0]

1import heapq
2from operator import itemgetter
3
4n = 3
5
6items = {'a': 7, 'b': 12, 'c': 9, 'd': 0, 'e': 24, 'f': 10, 'g': 24}
7
8topitems = heapq.nlargest(n, items.items(), key=itemgetter(1))  # Use .iteritems() on Py2
9topitemsasdict = dict(topitems)