1SELECT TOP 1 salary
2FROM (
3SELECT DISTINCT TOP N salary
4FROM #Employee
5ORDER BY salary DESC
6) AS temp
7ORDER BY salary
1SELECT first_name, last_name, salary, job_id
2FROM employees
3WHERE salary = (SELECT MIN(salary) FROM employees);
1SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
2WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
3
4
5OR
6
7Here is the solution for nth highest
8salary from employees table
9
10SELECT FIRST_NAME , SALARY FROM
11(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
12(ORDER BY SALARY DESC) AS SALARY_RANK
13FROM EMPLOYEES)
14WHERE SALARY_RANK = n;
1SELECT FIRST_NAME FROM EMPLOYEES
2WHERE SALARY = (SELECT MIN(SALARY) FROM EMPLOYEES);