1SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
2WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
1SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
2WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
3
4
5OR
6
7Here is the solution for nth highest
8salary from employees table
9
10SELECT FIRST_NAME , SALARY FROM
11(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
12(ORDER BY SALARY DESC) AS SALARY_RANK
13FROM EMPLOYEES)
14WHERE SALARY_RANK = n;
1SELECT MAX(salary) FROM Employee WHERE Salary NOT IN ( SELECT Max(Salary) FROM Employee);