java program to print all armstrong numbers between given range

1public class ArmstrongBetween1To1000
2{
3   public static void main(String[] args)
4   {
5      int number, n, total = 0;
6      System.out.println("Armstrong number between 1 to 1000: ");
7      for(int a = 1; a <= 1000; a++)
8      {
9         number = a;
10         while(number > 0)
11         {
12            n = number % 10;
13            total = total + (n * n * n);
14            number = number / 10;
15         }
16         if(total == a)
17         {
18            System.out.print(a + " ");
19         }
20         total = 0;
21      }
22   }
23}

1// Java program to print all armstrong numbers between given range
2import java.util.Scanner;
3public class ArmstrongNumbersGivenRange 
4{
5   public static void main(String[] args) 
6   {
7      int number, startNumber, endNumber, a, rem, n, count = 0;
8      Scanner sc = new Scanner(System.in);
9      System.out.println("Please enter starting number range: ");
10      startNumber = sc.nextInt();
11      System.out.println("Please enter ending number range: ");
12      endNumber = sc.nextInt();
13      for(a = startNumber + 1; a < endNumber; a++)
14      {
15         n = a;
16         number = 0;
17         while(n != 0)
18         {
19            rem = n % 10;
20            number = number + rem * rem * rem;
21            n = n / 10;
22         }
23         if(a == number)
24         {
25            if(count == 0)
26            {
27               System.out.println("Armstrong numbers between given range " + startNumber + " and " + endNumber + ": ");
28            }
29            System.out.print(a + "  ");
30            count++;
31         }
32      }
33      // if there is no Armstrong number found between range
34      if(count == 0)
35      {
36         System.out.println("Sorry!! There's no armstrong number between given range " + startNumber + " and " + endNumber);
37      }
38      sc.close();
39   }
40}

1import java.util.Scanner;
2
3/*
4 *@author: Mayank Manoj Raicha
5 * Armstrong Number in Java: A positive number is called armstrong number if it is equal to the sum of cubes of its digits 
6 * for example 0, 1, 153, 370, 371, 407 etc.
7 * 153 = (1*1*1)+(5*5*5)+(3*3*3)  = 1+125+27 = 153
8 */
9public class ArmstrongNumberExample {
10
11	public static void main(String[] args) {
12		
13		int sum = 0;
14		
15		Scanner in = new Scanner(System.in);
16		System.out.println("Enter the number: ");
17		int input = in.nextInt(); //1634
18		String val = String.valueOf(input);
19		char[] charArray = val.toCharArray();  //charArray[0] = "1" , charArray[1] = "6", charArray[2] = "3", charArray[3] = "4"
20		int[] numArray = new int[charArray.length]; //Declaring this array to store the result of getPowerOfNumber() method for each digit.
21		
22		//for each char element calculate the power of number and store it in the "cubedNumArray" array.
23		for(int i=0; i<charArray.length; i++) {
24			numArray[i] = getPowerOfNumber(Integer.parseInt(String.valueOf(charArray[i])), charArray.length);
25			sum = sum + numArray[i];
26		}
27		
28      //Compare if the resulting sum is equal to the original input.
29		if(sum == input) {
30			System.out.println("Entered number is an Armstrong number.");
31		}else {
32			System.out.println("Entered number is NOT an Armstrong number.");
33		}
34		
35		in.close();
36	}
37
38  	//Calculate & Return the value of the first argument raised to the power of the second argument
39	public static int getPowerOfNumber(int num, int count) {
40		return (int) Math.pow(num, count);
41	}
42}