find min number in java

1int[] arr = {2, 3, 4, 5, 6, 7, 8, 9,};
2        int max = arr[0]; // max tanimliyorsun
3        int min = arr[0];  // min tanimliyorsun
4
5        for (int i = 0; i < arr.length; i++) {
6            if (arr[i] > max){ 
7// array's index are compared with each other,
8// whichever is greater will be assigned to max
9                max = arr[i];
10            }
11            if(arr[i] < min){ 
12//array's index are compared with each other,
13// whichever is smaller will be assigned to min
14                min = arr[i];
15            }
16        }
17        System.out.println(max); // 9
18        System.out.println(min);  // 2
19

1 Scanner input = new Scanner(System.in);
2        // Minimum And Maximum 
3        int count = 0;
4        int min = 0;
5        int max = 0;
6        boolean bugSolved = true;
7		/* or we can use :
8        int min = Integer.MAX_VALUE;
9        int max = Integer.MIN_VALUE;
10        */
11		
12        while (true){
13            int cnt = count++;
14            System.out.print("Enter Number #"+(cnt+1)+": ");
15            boolean isValid = input.hasNextInt();
16            if(isValid){
17               int num = input.nextInt();
18               /* if (bugSolved){
19                   bugSolved = false;
20                   min = num;
21                   max = num;
22               }  # Just remove this condition and 
23               	boolean (bugSolved) at the top, if you use 
24               	int min = Integer.MAX_VALUE and int max = 
25                Integer.MIN_VALUE */
26                if (num < min) {
27                    min = num;
28                }else if (num > max){
29                    max = num;
30                }
31            }else{
32                System.out.println("Invalid input..");
33                break;
34            }
35            input.nextLine();
36        }
37        System.out.println("Min Number : " + min);
38        System.out.println("Max Number : " + max);