filter duplicate value in array of object typescript

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showing results for - "filter duplicate value in array of object typescript"
Lily-Rose
22 Jul 2019
1let person = [{name: "john"}, {name: "jane"}, {name: "imelda"}, {name: "john"}];
2
3function removeDuplicates(data, key) {
4  
5  return [
6    ...new Map(data.map(item => [key(item), item])).values()
7  ]
8
9};
10
11console.log(removeDuplicates(person, item => item.name));
Shayna
30 Mar 2020
1let person = [
2{name: "john"}, 
3{name: "jane"}, 
4{name: "imelda"}, 
5{name: "john"},
6{name: "jane"}
7];
8
9const data = Array.from(new Set(person.map(JSON.stringify))).map(JSON.parse);
10console.log(data);
Moritz
29 Sep 2020
1let person = [
2{name: "john"}, 
3{name: "jane"}, 
4{name: "imelda"}, 
5{name: "john"},
6{name: "jane"}
7];
8
9const obj = [...new Map(person.map(item => [JSON.stringify(item), item])).values()];
10console.log(obj);
Cyril
07 Jan 2021
1var arrOfObj = [
2  {
3    id:1 ,name:'abc',age:27
4  },
5  {
6    id:2 ,name:'pqr',age:27
7  },
8  {
9    id:1 ,name:'abc',age:27
10  },
11 ]
12
13var setObj = new Set(); // create key value pair from array of array
14
15var result = arrOfObj.reduce((acc,item)=>{
16  if(!setObj.has(item.age)){
17    setObj.add(item.age)
18    acc.push(item)
19  }
20  return acc;
21},[]);//converting back to array from mapobject
22
23console.log(result);
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