remove duplicates from array of objects javascript

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showing results for - "remove duplicates from array of objects javascript"
Logan
11 Jan 2017
1const arr = [{id: 1, name: 'one'}, {id: 2, name: 'two'}, {id: 1, name: 'one'}]
2
3const ids = arr.map(o => o.id)
4const filtered = arr.filter(({id}, index) => !ids.includes(id, index + 1))
5
6console.log(filtered)
Chanelle
19 Jun 2018
1this.item = this.item.filter((el, i, a) => i === a.indexOf(el))
Anya
15 Jan 2018
1//check one attribute
2let person = [{name: "john"}, {name: "jane"}, {name: "imelda"}, {name: "john"}];
3
4person = person.filter((item, index, self) =>
5  index === self.findIndex((t) => (
6    t.name === item.name
7  ))
8)
9
10//check two attributes
11let person = [{place: "uno", name: "john"}, {place: "duno", name: "jane"}, {place: "duno" ,name: "imelda"}, {place: "uno" ,name: "john"}];
12
13person = person.filter((item, index, self) =>
14  index === self.findIndex((t) => (
15    t.place === item.place && t.name === item.name
16  ))
17)
Lucia
09 Aug 2018
1const addresses = [...]; // Some array I got from async call
2
3const uniqueAddresses = Array.from(new Set(addresses.map(a => a.id)))
4 .map(id => {
5   return addresses.find(a => a.id === id)
6 })
Keziah
14 Sep 2018
1let arr = [{name: "john"}, {name: "jane"}, {name: "imelda"}, {name: "john"}];
2
3const uniqueArray = arr.filter((v,i,a)=>a.findIndex(t=>(t.name===v.name))===i)
4console.log(uniqueArray);
Iker
20 Nov 2017
1arr.filter((v,i,a)=>a.findIndex(t=>(t.place === v.place && t.name===v.name))===i)
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