c 2b 2b sum up numbers

1// Method 1: Mathematical -> Sum up numbers from 1 to n 
2int sum(int n){
3	return (n * (n+1)) / 2;
4}
5
6// Method 2: Using a for-loop  -> Sum up numbers from 1 to n 
7int sum(int n){
8	int tempSum = 0; 
9  	for (int i = n; i > 0; i--){
10     	tempSum += i;  
11    }
12  	return tempSum; 
13}
14
15// Method 3: Using recursion -> Sum up numbers from 1 to n 
16int sum(int n){
17	return n > 0 ? n + sum(n-1) : 0; 
18}

1// Method 1: Mathematical -> Sum up numbers from 1 to n 
2int sum(int n){
3	return (n * (n+1)) / 2;
4}
5
6// Method 2: Using a for-loop -> Sum up numbers from 1 to n 
7int sum(int n){
8	int tempSum = 0; 
9  	for (int i = n; i > 0; i--){
10     	tempSum += i;  
11    }
12  	return tempSum; 
13}
14
15// Method 3: Using recursion -> Sum up numbers from 1 to n 
16int sum(int n){
17	return n > 0 ? n + sum(n-1) : 0; 
18}

1#include<iostream>
2using namespace std;
3int main()
4{
5	double number1,number2;
6  	double sum0;
7  	sum=number1+number2;
8  	cout<<sum;
9}