c 2b 2b sum of even and odd numbers

1//given the fact that it takes n of number
2void sumEvenAndOdd(){
3int n=0 , evenSum=0 , oddSum=0;
4     int numbers[Size];
5     cout<<"enters the number(N) of integers\n";
6     cin>>Size;
7
8     cout<<"Enter "<<Size<<" number/s:\n";
9     for(int i =0 ;i< Size ; ++i){
10        cin>>numbers[i];
11     }
12     for(int i =0 ;i<Size ; ++i){
13        if(numbers[i]%2 ==0){
14            evenSum += numbers[i];
15        }
16        else{
17            oddSum += numbers[i];
18        }
19     }
20     cout<<"the sum of even numbers is : "<<evenSum <<"\nthe sum of odd numbers is :"<<oddSum<<endl;
21}