typescript sort array of objects

1const list = [
2  { color: 'white', size: 'XXL' },
3  { color: 'red', size: 'XL' },
4  { color: 'black', size: 'M' }
5]
6
7list.sort((a, b) => (a.color > b.color) ? 1 : -1)

1const books = [
2  {id: 1, name: 'The Lord of the Rings'},
3  {id: 2, name: 'A Tale of Two Cities'},
4  {id: 3, name: 'Don Quixote'},
5  {id: 4, name: 'The Hobbit'}
6]
7
8compareObjects(object1, object2, key) {
9  const obj1 = object1[key].toUpperCase()
10  const obj2 = object2[key].toUpperCase()
11
12  if (obj1 < obj2) {
13    return -1
14  }
15  if (obj1 > obj2) {
16    return 1
17  }
18  return 0
19}
20
21books.sort((book1, book2) => {
22  return compareObjects(book1, book2, 'name')
23})
24
25// Result:
26// {id: 2, name: 'A Tale of Two Cities'}
27// {id: 3, name: 'Don Quixote'}
28// {id: 4, name: 'The Hobbit'}
29// {id: 1, name: 'The Lord of the Rings'}

1function sortByDate( a, b ) {
2  if ( a.created_at < b.created_at ){
3    return -1;
4  }
5  if ( a.created_at > b.created_at ){
6    return 1;
7  }
8  return 0;
9}
10
11myDates.sort(sortByDate);//myDates is not sorted.

1list.sort((a, b) => (a.color > b.color) ? 1 : (a.color === b.color) ? ((a.size > b.size) ? 1 : -1) : -1 )
2