typescript algorithm to find repeating number sequences over time

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Olivia
11 Sep 2019
1String arr[] = {"12341234abc", "1234foo1234", "12121212", "111111111", "1a1212b123123c12341234d1234512345"};
2String regex = "(\\d+?)\\1";
3Pattern p = Pattern.compile(regex);
4for (String elem : arr) {
5    boolean noMatchFound = true;
6    Matcher matcher = p.matcher(elem);
7    while (matcher.find()) {
8        noMatchFound = false;
9        System.out.println(elem + " got repeated: " + matcher.group(1));
10    }
11    if (noMatchFound) {
12        System.out.println(elem + " has no repeation");
13    }
14}
15
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