tostring convert to long

1
2long l = 12345L;
3String str = Long.toString(l);
4System.out.println(str); //prints '12345'
5

1
2long l = 12345L;
3String str = new StringBuilder().append(l).toString();
4

1
2long l = 0x11L;
3String str = Long.toString(l);
4System.out.println(str); //prints '17'
5l = 011L;
6str = Long.toString(l);
7System.out.println(str); //prints '9'
8

1
2package com.journaldev.string;
3
4import java.text.DecimalFormat;
5
6public class JavaLongToString {
7
8	@SuppressWarnings("deprecation")
9	public static void main(String[] args) {
10		long l = 12345L;
11		String str = Long.toString(l);
12		System.out.println(str);
13
14		str = String.valueOf(l);
15		System.out.println(str);
16
17		// deprecated from Java 9, use valueOf for better performance
18		str = new Long(l).toString();
19		System.out.println(str);
20
21		str = String.format("%d", l);
22		System.out.println(str);
23
24		str = l + "";
25		System.out.println(str);
26
27		str = DecimalFormat.getNumberInstance().format(l);
28		System.out.println(str);
29
30		str = new DecimalFormat("#").format(l);
31		System.out.println(str);
32
33		str = new StringBuilder().append(l).toString();
34		System.out.println(str);
35	}
36}
37

1
2long l = 12345L;
3//deprecated from Java 9, use valueOf for better performance
4String str = new Long(l).toString(); // str is '12345'
5

1
2long l = 369L;
3String s = String.format("%d", l);
4

1
2long l = 12345L;
3String str = String.valueOf(l); // str is '12345'
4

1
2long number = 45;
3System.out.println(Long.toBinaryString(number)); //101101
4System.out.println(Long.toOctalString(number)); //55
5System.out.println(Long.toHexString(number)); //2d
6System.out.println(Long.toString(number, 5)); //140
7

1
2long l = 12345L;
3String str = DecimalFormat.getNumberInstance().format(l);
4System.out.println(str); //str is '12,345'
5//if you don't want formatting
6str = new DecimalFormat("#").format(l);
7System.out.println(str); //str is '12345'
8