sum of numbers in python

1sum(list(map(int,input().split())))
2

1>>> list = [1, 2, 3]
2>>> sum(list)
36

1digit_sum = lambda s: sum(int(digit) for digit in str(s)) #without recursion
2
3#sum of digits using recursion
4
5dsum = 0 # we define dsum outside of the function so its value isn't reset every time the function gets called recursivley
6
7def rdigit_sum(s):
8    global dsum # making dsum 'global' allows us to use it a function
9    if s: # checks if s has digits to add to dsum
10        dsum += s%10 # adds the current units digit to dsum
11        s = s//10 # removes the current units digit
12    else: # if there are no digits left
13        s = dsum  # this block reassigns s to dsum, then resets dsum to 0 so dsum doesn't already have a value if this function is called more than once in a program
14        dsum = 0
15        return s  
16    return rdigit_sum(s) # this is the 'recursive' part of the program that calls the function again

1def sum_(n):
2    if n == 0:
3        return n
4    else:
5        prev_n = sum_(n - 1)
6        result = prev_n + n
7        return result
8
9
10s = sum_(5)
11
12print(s)
13
14#Output:
15# 15

1def SumNum(mylist):
2    the_sum = sum(filter(lambda i: isinstance(i, (int, long, float)), mylist))
3    return the_sum