str 5bi 5d 270 27
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showing results for - "str 5bi 5d 270 27"
María
07 Jan 2017
1The part str[i] - '0' takes the ASCII character of the corresponding digit
2which are sequentially "0123456789" and subtracts the code for '0' from the
3current character. This leaves a number in the range 0..9 as to which digit is
4in that place in the string.
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str 280 29void print24 28string str 29 7b int h1 3d 28int 29str 5b1 5d 270 27 3b int h2 3d 28int 29str 5b0 5d 270 27 3b int hh 3d 28h2 2a10 2bh1 2510 29 3b if 28str 5b8 5d 3d 3d 27a 27 29 7b if 28hh 3d 3d 12 29 7bstr 5bi 5d 270 27str 28a 5b0 5d 29strcmp 5c0c 2b 2b str 5bi 5d 270 27 28str1 5bi 5d 270 27 29str 5bi 5d 270 27 your answer for
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