square root c 2b 2b

Solutions on MaxInterview for square root c 2b 2b by the best coders in the world

showing results for - "square root c 2b 2b"
Hugo
18 Sep 2018
1#include <cmath>
2sqrt(x);
Carolina
04 Jul 2020
1#include <math.h>
2
3//get square root of a number "b"
4int main(){
5  	int a = 2; //declare number you want to take square root of
6  	int sqrtNum = sqrt (a); //assign the sqrt value to a variable
7  	cout << sqrtNum << endl;
8	return 0;
9}
Christian
27 Feb 2020
1#include <stdlib.h>
2#include <stdio.h>
3#include <math.h>
4
5/*
6square root of a number
7*/
8
9int main(){
10float num, raiz;
11printf("enter a number: \t");
12scanf("%f",&num);
13raiz = sqrt(num);
14printf("The square root of %f is: %f.\n", num, raiz);
15system("pause");
16return 0;    
17}
Allison
22 Feb 2018
1#include <iostream>
2#include <cmath>
3using namespace std;
4
5int main()
6{
7	int x = 625;
8	int result = sqrt(x);
9	cout << "Square root of " << x << " is " << result << endl;
10	return 0;
11}
Finn
05 Nov 2016
1#include <math.h>
2
3double sqrt(double x) {
4    if (x <= 0)
5        return 0;       // if negative number throw an exception?
6    int exp = 0;
7    x = frexp(x, &exp); // extract binary exponent from x
8    if (exp & 1) {      // we want exponent to be even
9        exp--;
10        x *= 2;
11    }
12    double y = (1+x)/2; // first approximation
13    double z = 0;
14    while (y != z) {    // yes, we CAN compare doubles here!
15        z = y;
16        y = (y + x/y) / 2;
17    }
18    return ldexp(y, exp/2); // multiply answer by 2^(exp/2)
19}
20
Yannic
24 Mar 2017
1#include <cmath> //library for the function 
2
3sqrt(variable);
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