return an array in c 2b 2b

1#include <iostream> 
2using namespace std; 
3  
4int* fun() 
5{ 
6    int* arr = new int[100]; 
7  
8    /* Some operations on arr[] */
9    arr[0] = 10; 
10    arr[1] = 20; 
11  
12    return arr; 
13} 
14  
15int main() 
16{ 
17    int* ptr = fun(); 
18    cout << ptr[0] << " " << ptr[1]; 
19    return 0; 
20} 

1int * fillarr(int arr[], int length){
2   for (int i = 0; i < length; ++i){
3      // arr[i] = ? // do what you want to do here
4   }
5   return arr;
6}
7
8// then where you want to use it.
9int main(){
10int arr[5];
11int *arr2;
12
13arr2 = fillarr(arr, 5);
14
15}
16// at this point, arr & arr2 are basically the same, just slightly
17// different types.  You can cast arr to a (char*) and it'll be the same.
18

1#include <iostream>
2#include <ctime>
3
4using namespace std;
5
6// function to generate and retrun random numbers.
7int * getRandom( ) {
8
9   static int  r[10];
10
11   // set the seed
12   srand( (unsigned)time( NULL ) );
13   
14   for (int i = 0; i < 10; ++i) {
15      r[i] = rand();
16      cout << r[i] << endl;
17   }
18
19   return r;
20}
21
22// main function to call above defined function.
23int main () {
24
25   // a pointer to an int.
26   int *p;
27
28   p = getRandom();
29   
30   for ( int i = 0; i < 10; i++ ) {
31      cout << "*(p + " << i << ") : ";
32      cout << *(p + i) << endl;
33   }
34
35   return 0;
36}