showing results for - "react native jsx loop with number"
Marie
21 Jan 2016
1    
2Count wiil be my number value = 10;
3
4
5
6const {Count} = props;
7    let list =  Count=== undefined?10:Count;
8    let jsx = [];
9    for (let index = 0; index < list; index++) {
10        jsx.push('index'+index)
11    }
12
13  return (
14        <View>
15            <Text>{jsx.length}</Text>
16        {jsx.map(()=>(
17        <Text>{index}</Text>
18         ))
19        }
20        </View>
21
22    )
23    
24==========================
25  
26  
27if you try like this 
28jsx = new Array(list);
29
30this will create array but jsx is not working
31
32try your self 
33
Alexis
22 Aug 2020
1import React from 'react';
2import './App.css';
3
4
5let items=['Item 1','Item 2','Item 3','Item 4','Item 5'];
6let itemList=[];
7items.forEach((item,index)=>{
8  itemList.push( <li key={index}>{item}</li>)
9})
10function App() {
11  
12  return (
13    <>
14   
15      <h2>This is a simple list of items</h2>
16      <ul>
17        {itemList}
18      </ul>
19    </>
20  );
21}
22
23export default App;
24
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