python unknow number of arguments 2c default argument 2c

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10 Oct 2020

1def foo(a, b=3, *args, **kwargs):
2  defaultKwargs = { 'c': 10, 'd': 12 }
3  kwargs = { **defaultKwargs, **kwargs }
4  print(a, b, args, kwargs)
5  
6  # Do something    
7
8foo(1) # 1 3 () {'c': 10, 'd': 12}
9foo(1, d=5) # 1 3 () {'c': 10, 'd': 5}
10foo(1, 2, 4, d=5) # 1 2 (4,) {'c': 10, 'd': 5}
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