python remove by index

1>>> l = [1, 2, 43, 3, 4]
2>>> l.pop(2) #enter the index as argument
343
4>>> l
5[1, 2, 3, 4]

1>>> del a[2:4]
2>>> a
3[0, 1, 4, 5, 6, 7, 8, 9]

1a = ['a', 'b', 'c', 'd']
2a.pop(1)
3
4# now a is ['a', 'c', 'd']

1a = [0, 1, 2, 3, 4, 5]
2el = a.pop(2)

1arr = [0, 1, 2, 3, 4]
2del arr[1]
3# arr is now equal to [0, 2, 3, 4]