python range reverse

1When you call range() with three arguments, you can choose not only 
2where the series of numbers will start and stop but also how big the 
3difference will be between one number and the next.
4
5range(start, stop, step)
6
7If your 'step' is negative and 'start' is bigger than 'stop', then 
8you move through a series of decreasing numbers.
9
10for i in range(10,0,-1):
11    print(i, end=' ')
12# Output: 10 9 8 7 6 5 4 3 2 1

1# 1.
2for i in reversed(range(3)): # output: 	0
3    print(i)				 #			1
4    						 # 			2
5# works with arrays as well , reversed(arr)
6
7# 2.
8# another alternative is
9arr = [1,2,3]
10# note: arr[start : end : step]
11for i in arr[::-1]:			 # output:	0
12  print(i)					 # 			1
13  							 #			2
14
15# 3.
16# last alternative i don't recommened!
17# note: range(start, end, step)
18for i in range(len(arr) - 1, -1 , -1): 	# output: 	0
19  print(i)								# 			1
20  										# 			2
21# read more on range() to understand even better how it works has the same rules as the arrays

1my_list = [1, 2, 3]
2my_list.reverse()           # my_list is modified
3print(my_list)              # '[3, 2, 1]'
4my_revert = my_list[::-1]   # my_list stays [3, 2, 1]
5print(my_revert)            # '[1, 2, 3]'
6# Item by item reverse with range(<start>, <end>, <step>)
7for i in range(len(my_list), 0, -1):		# my_list is [3, 2, 1]
8    print(my_list[i-1])		# '1' '2' '3'
9for i in reversed(range(len(my_list))):
10    print(my_list[i])       # '1' '2' '3'

1>>> type(range(3))
2<class 'range'>
3