python extract zip file without directory structure

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showing results for - "python extract zip file without directory structure"
Aubree
16 Oct 2020
1import zipfile
2
3archive = zipfile.ZipFile('archive.zip')
4
5for file in archive.namelist():
6    if file.startswith('foo/'):
7        archive.extract(file, 'destination_path')
Kaylin
11 Oct 2019
1import os
2import shutil
3import zipfile
4
5my_dir = r"D:\Download"
6my_zip = r"D:\Download\my_file.zip"
7
8with zipfile.ZipFile(my_zip) as zip_file:
9    for member in zip_file.namelist():
10        filename = os.path.basename(member)
11        # skip directories
12        if not filename:
13            continue
14
15        # copy file (taken from zipfile's extract)
16        source = zip_file.open(member)
17        target = open(os.path.join(my_dir, filename), "wb")
18        with source, target:
19            shutil.copyfileobj(source, target)
Angelina
26 Oct 2017
1ZipFile.extractall(path=None, members=None, pwd=None)
2
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