python exit loop iteration

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showing results for - "python exit loop iteration"
Bruno
11 Nov 2019
1# python 3
2
3for x in range(1, 10):
4    print(x)
5    if x == 4:
6        break
7# prints 1 to 4
8
Valeria
15 Sep 2016
1alphabet = ['a' , 'b' , 'c' , 'd' ]
2for letter in alphabet:
3  if letter == 'b' :
4    continue
5    #continues to next iteration
6  print( letter )
7for letter in alphabet:
8  if letter == 'b' :
9    break
10    #terminates current loop
11  print( letter )
12for letter in alphabet:
13  if letter == 'b' :
14    pass
15    #does nothing
16  print( letter )
Frieda
15 Mar 2019
1print("enter a number")
2num=int(input())
3for i in range(2,num+1):
4    if(num%i==0):
5        print("smallest divisor is",i)
6        break
7        
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