pandas df by row index

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showing results for - "pandas df by row index"
Lilly
19 Aug 2019
1indices = [133, 22, 19, 203, 14, 1]
2df_by_indices = df.iloc[indices, :]
source
Maria
01 May 2019
1rowData = dfObj.loc[ 'b' , : ]
2
source
Elias
11 Mar 2016
1In [1]: df = pd.DataFrame(np.random.rand(5,2),index=range(0,10,2),columns=list('AB'))
2
3In [2]: df
4Out[2]: 
5          A         B
60  1.068932 -0.794307
72 -0.470056  1.192211
84 -0.284561  0.756029
96  1.037563 -0.267820
108 -0.538478 -0.800654
11
12In [5]: df.iloc[[2]]
13Out[5]: 
14          A         B
154 -0.284561  0.756029
16
17In [6]: df.loc[[2]]
18Out[6]: 
19          A         B
202 -0.470056  1.192211
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