mongodb aggregate group

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08 May 2018

1#It's the equivalent of the following SQL instruction:
2# SELECT COUNT(*) FROM Table
3# GROUP BY your_field
4# HAVING COUNT(*) > N
5query = db.collection.aggregate([
6
7    { 
8      "$group": { "_id": "$your_field", #GROUP BY your_field
9    			"count": {"$sum":1} }   #COUNT(*)
10    },
11    
12    { "$match": { "count": { "$gt": N } } } #HAVING COUNT(*) > N
13])

source

Edouard

20 Jan 2020

1#equivalent of the following SQL instruction:
2# SELECT COUNT(*) FROM Table
3# GROUP BY your_field
4query = db.collection.aggregate([
5    { 
6        "$group": {
7            "_id": "$your_field", #GROUP BY your_field
8            "total": {"$sum":1}   #COUNT(*)
9        }
10    }
11])

Matilda

17 Jun 2019

1db.sales.aggregate([
2  // First Stage
3  {
4    $match : { "date": { $gte: new ISODate("2014-01-01"), $lt: new ISODate("2015-01-01") } }
5  },
6  // Second Stage
7  {
8    $group : {
9       _id : { $dateToString: { format: "%Y-%m-%d", date: "$date" } },
10       totalSaleAmount: { $sum: { $multiply: [ "$price", "$quantity" ] } },
11       averageQuantity: { $avg: "$quantity" },
12       count: { $sum: 1 }
13    }
14  },
15  // Third Stage
16  {
17    $sort : { totalSaleAmount: -1 }
18  }
19 ])
20

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