minimum number of deletions to make a string palindrome

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Janae
07 Jan 2018
1//Code by @soumyadeepp : Soumyadeep Ghosh
2
3//A very Simple DP problem. Just find the length of the Longest common subsequence 
4//of the string and its reverse. Now subtract this length from the actual length
5//of the substring. That's it.
6
7#include <bits/stdc++.h>
8
9using namespace std;
10
11int lps(string s)
12{
13	string r = s;
14	reverse(r.begin(),r.end());
15	int sz1 = s.size();
16	int dp[sz1+1][sz1+1];
17	
18	for(int i = 0 ; i <= sz1 ; i++)
19	{
20		dp[0][i] = 0;
21		dp[i][0] = 0;
22	}
23	for(int i = 1; i <= sz1; i++)
24	{
25		for(int j = 1; j <= sz1 ; j++)
26		{
27			if(s[i-1] == r[j-1])
28			{
29				dp[i][j] = dp[i-1][j-1] + 1;
30			}
31			else
32			dp[i][j] = max(dp[i-1][j],dp[i][j-1]);
33		}
34	}
35	return dp[sz1][sz1];
36}
37int main()
38{
39	int t;
40	cin>>t;
41	while(t--)
42	{
43		string s;
44		cin>>s;
45		int ans = s.size() - lps(s);
46		cout<<ans<<endl;
47	}
48}
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