javascript reduce sum

1console.log(
2  [1, 2, 3, 4].reduce((a, b) => a + b, 0)
3)
4console.log(
5  [].reduce((a, b) => a + b, 0)
6)

1const arrSum = arr => arr.reduce((a,b) => a + b, 0)

1arrSum = function(arr){  return arr.reduce(function(a,b){    return a + b  }, 0);}

1let nums = [1, 2, 3];
2
3nums.reduce((curr, next) => curr + next);

1[1,2,3,4,5].reduce((acc, current)=>acc+current, 0)