java code to reverse an integer

1public class ReverseNumber {
2    public static void main(String[] args) {
3        int num = 1234, reversed = 0;
4
5        while(num != 0) {
6            int digit = num % 10;
7            reversed = reversed * 10 + digit;
8            num = num / 10;
9        }
10        System.out.println("Reversed Number: " + reversed);
11}}

1public class ReverseNumberExample1   
2{  
3public static void main(String[] args)   
4{  
5int number = 987654, reverse = 0;  
6while(number != 0)   
7{  
8int remainder = number % 10;  
9reverse = reverse * 10 + remainder;  
10number = number/10;  
11}  
12System.out.println("The reverse of the given number is: " + reverse);  
13}  
14}  

1while(num != 0) 
2{
3   int digit = num % 10;
4   reversed = reversed * 10 + digit;
5   num /= 10;
6}

1//continue to loop until  a value is equal to 0
2
3public class ReverseNum{
4  
5  public static void main(String[] args {
6  
7  int a = 543;
8  int reverse = 0;
9  
10 while(a!=0){ //itera the process
11 
12 int digit = a%10; //isolate the last digit number
13 
14 reverse = digit + (reverse*10); //append last digit to reverse
15 a=a/10; // remove the last digit from number
16   } 
17   System.out.println(reverse);
18   
19     } }

1int rev= 0;
2while(num > 9)
3{
4  rev= rev*10 + num%10;
5  num/= 10;
6}