java check if element exists in array

1import java.util.Arrays;
2
3// For String
4String[] array = {"Boto", "Nesto", "Lepta"};
5String toSearch = "Nesto";
6
7// Inline
8if (Arrays.toString(array).contains(toSearch)) {
9	// Do something if it's found
10}
11
12// Multi line
13String strArray = Array.toString(array);
14if (strArray.contains(toSearch)) {
15	// Do your thing
16}
17
18// Different elements
19int[] numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0};
20int number = 5;
21
22String checker = Arrays.toString(numbers);
23
24// The toString of int in some cases can happen without explicitly saying so
25// In this example we convert both
26if (checker.contains(Integer.toString(number)) {
27	// Found.     
28}
29

1package com.mkyong.core;
2
3import java.util.Arrays;
4import java.util.List;
5
6public class StringArrayExample1 {
7
8    public static void main(String[] args) {
9
10        String[] alphabet = new String[]{"A", "B", "C"};
11
12        // Convert String Array to List
13        List<String> list = Arrays.asList(alphabet);
14        
15        if(list.contains("A")){
16            System.out.println("Hello A");
17        }
18
19    }
20
21}
22Copy

1	// Convert to stream and test it
2	boolean result = Arrays.stream(alphabet).anyMatch("A"::equals);
3	if (result) {
4		System.out.println("Hello A");
5	}
6Copy