java anagrams

1import java.util.Arrays;  
2   
3public class AnagramString {  
4    static void isAnagram(String str1, String str2) {  
5        String s1 = str1.replaceAll("\\s", "");  
6        String s2 = str2.replaceAll("\\s", "");  
7        boolean status = true;  
8        if (s1.length() != s2.length()) {  
9            status = false;  
10        } else {  
11            char[] ArrayS1 = s1.toLowerCase().toCharArray();  
12            char[] ArrayS2 = s2.toLowerCase().toCharArray();  
13            Arrays.sort(ArrayS1);  
14            Arrays.sort(ArrayS2);  
15            status = Arrays.equals(ArrayS1, ArrayS2);  
16        }  
17        if (status) {  
18            System.out.println(s1 + " and " + s2 + " are anagrams");  
19        } else {  
20            System.out.println(s1 + " and " + s2 + " are not anagrams");  
21        }  
22    }  
23   
24    public static void main(String[] args) {  
25        isAnagram("Keep", "Peek");  
26        isAnagram("Mother In Law", "Hitler Woman");  
27    }  
28}  
29/*OUTPUT
30*Keep and Peek are anagrams
31*MotherInLaw and HitlerWoman are anagrams
32*/

1    static boolean isAnagram(String a, String b) {
2        
3        String sortedA = "";
4        Object[] aArr = a.toLowerCase().chars().sorted().mapToObj(i -> (char) i).toArray();
5        for (Object o: aArr) {
6            sortedA = sortedA.concat(o.toString());
7        }
8        
9        
10        String sortedB = "";
11        Object[] bArr = b.toLowerCase().chars().sorted().mapToObj(i -> (char) i).toArray();
12        for (Object o: bArr) {
13            sortedB = sortedB.concat(o.toString());
14        }
15        
16        if(sortedA.equals(sortedB))    
17            return true;
18        else
19            return false;    
20    }