insertion sort in python

1def insertionSort(alist):
2
3   for i in range(1,len(alist)):
4
5       #element to be compared
6       current = alist[i]
7
8       #comparing the current element with the sorted portion and swapping
9       while i>0 and alist[i-1]>current:
10           alist[i] = alist[i-1]
11           i = i-1
12          alist[i] = current
13
14       #print(alist)
15
16   return alist
17
18print(insertionSort([5,2,1,9,0,4,6]))

1def insertion(s):
2    for i in range(0,len(s)-1):
3        if s[i]>s[i+1]:
4            s[i],s[i+1]=s[i+1],s[i]
5            for j in range(i,0,-1):
6                if s[j]<s[j-1]:
7                    s[j],s[j-1]=s[j-1],s[j]
8    print(s)
9    
10insertion([5,2,1,9,0,4,6])

1#Insertion sort
2ar = [34, 42, 22, 54, 19, 5]
3
4for i in range(1, len(ar)):
5    while ar[i-1] > ar[i] and i > 0:
6        ar[i-1], ar[i] = ar[i], ar[i-1]
7        i -= 1
8print(ar)
9

1// Por ter uma complexidade alta,
2// não é recomendado para um conjunto de dados muito grande.
3// Complexidade: O(n²) / O(n**2) / O(n^2)
4// @see https://www.youtube.com/watch?v=TZRWRjq2CAg
5// @see https://www.cs.usfca.edu/~galles/visualization/ComparisonSort.html
6
7function insertionSort(vetor) {
8    let current;
9    for (let i = 1; i < vetor.length; i += 1) {
10        let j = i - 1;
11        current = vetor[i];
12        while (j >= 0 && current < vetor[j]) {
13            vetor[j + 1] = vetor[j];
14            j--;
15        }
16        vetor[j + 1] = current;
17    }
18    return vetor;
19}
20
21insertionSort([1, 2, 5, 8, 3, 4])