1>>> the_list = [1,2,3]
2>>> reversed_list = the_list.reverse()
3>>> list(reversed_list)
4[3,2,1]
5
6OR
7
8>>> the_list = [1,2,3]
9>>> the_list[::-1]
10[3,2,1]
1 List<String> stringList = Arrays.asList("A", "B", "C");
2 Collections.reverse(stringList);
3 assertThat(stringList).containsExactly("C", "B", "A");
1my_list = [1, 2, 3]
2my_list.reverse() # my_list is modified
3print(my_list) # '[3, 2, 1]'
4my_revert = my_list[::-1] # my_list stays [3, 2, 1]
5print(my_revert) # '[1, 2, 3]'
6# Item by item reverse with range(<start>, <end>, <step>)
7for i in range(len(my_list), 0, -1):
8 print(my_list[i-1]) # '1' '2' '3'
9for i in reversed(range(len(my_list))):
10 print(my_list[i]) # '1' '2' '3'
1# reversing a list in Python
2numbers = [1,2,3,4,5,6,7,8,9]
3print(numbers[::-1])