how to read space separated integers in java

1String s[]= scanner.nextLine().split(" ");for(int i =0 ;i < s.length;i++){    a[i]= Integer.parseInt(s[i]);}

1 Scanner scanner = new Scanner(System.in);
2 int numOfBlocks = scanner.nextInt();
3 int weightArray[] = new weightArray[numOfBlocks];
4 for(int i=0;i<numOfBlocks;i++)
5       {
6        weightArray[i] = scanner.nextInt();
7       }
8 scanner.close();
9//your logic

1import java.io.BufferedReader;
2import java.io.IOException;
3import java.io.InputStreamReader;
4
5class BufferedReaderTest
6{
7    public static void main(String[] args) throws IOException {
8        BufferedReader bi = new BufferedReader(new InputStreamReader(System.in));
9
10        int num[] = new int[1000];
11        String[] strNums;
12        long startTime, endTime;
13
14
15        /*________ TEST STARTS ________*/
16        startTime = System.nanoTime();
17        strNums = bi.readLine().split("\\s");
18        for(int i=0; i<strNums.length; i++) {
19            num[i] = Integer.parseInt(strNums[i]);
20        }
21        endTime = System.nanoTime();
22        /*________ TEST ENDS ________*/
23
24        System.out.println("Total Time Taken: " + (endTime - startTime));
25    }
26}
27

1# if you read from console
2
3	Scanner scanner = new Scanner(System.in);
4	List<Integer> list = new ArrayList<Integer>();
5	while (scanner.hasNextInt())
6  		list.add(scanner.nextInt());
7	int[] arr = list.toArray(new int[0]);
8
9# if you read from file
10
11	try {
12      	File myObj = new File("filename.txt");
13      	Scanner myReader = new Scanner(myObj);
14      	while (myReader.hasNextInt()) { // check for next integer in file
15        	String data = myReader.nextInt(); // read the integer
16        	System.out.println(data);
17      	}
18      	myReader.close();
19    } catch (FileNotFoundException e) {
20      	System.out.println("An error occurred.");
21      	e.printStackTrace();
22    }