how to pass a dynamic 2d array to a function c

1#include <stdio.h>
2#include <stdlib.h>
3
4// Here the parameter is an array of pointers
5void assign(int** arr, int m, int n)
6{
7	for (int i = 0; i < m; i++) {
8		for (int j = 0; j < n; j++) {
9			arr[i][j] = i + j;
10		}
11	}
12}
13
14// Program to pass 2D array to a function in C
15int main(void)
16{
17	int m = 5;
18	int n = 5;
19
20	// dynamically create array of pointers of size m
21	int **arr = (int **)malloc(m * sizeof(int *));
22
23	// dynamically allocate memory of size n for each row
24	for (int r = 0; r < m; r++)
25		arr[r] = (int *)malloc(n * sizeof(int));
26
27	assign(arr, m, n);
28
29	// print 2D array
30	for (int i = 0; i < m; i++) {
31		for (int j = 0; j < n; j++) {
32			printf("%3d", arr[i][j]);
33		}
34		printf("\n");
35	}
36
37	// deallocate memory
38	for (int i = 0; i < m; i++)
39		free(arr[i]);
40	free(arr);
41
42	return 0;
43}