how to find runner up score in python

1price=[10,20,4,5,4,6,46,43,4,64,65,8,45,55,558,15,5,4,6,5,255,5]
2price.sort()
3price.reverse()
4max=price[0]
5sec_max=price[1]
6print(price)
7print(f"the max is {max}, runner up is {sec_max}")

1from collections import Counter
2if __name__ == '__main__':
3    n = int(raw_input())
4    arr = Counter(map(int, raw_input().split())).keys()
5    arr.sort()
6    print arr[-2]
7

1n = int(input())
2arr = list(map(int, input().split()))
3zes = max(arr)
4i=0
5while(i<n):
6    if zes ==max(arr):
7        arr.remove(max(arr))
8    i+=1
9print(max(arr))
10#note: do not  use set() will not work for negative numbers
11# contact me : sandeshbhat2000@gmail.com

1if __name__ == '__main__':
2    n = int(input())
3    arr = map(int, input().split())
4    arr = list(arr)
5    x = max(arr)
6    y = -9999999
7    for i in range(0,n):
8        if arr[i]<x and arr[i] > y:
9            y = arr[i]
10    
11    print(y)
12

1if __name__ == '__main__':
2    n = int(input())
3    arr = map(int, input().split())
4    lista = list(arr)
5    lista.sort()
6    maximo = max(lista)
7    for actual in reversed(lista):
8        if actual == maximo:
9            lista.remove(max(lista))
10    
11    print(max(lista))
12