how to find largest number in list python without max

1Numbers = [90,78,34,50,100,99]
2higest_number = 0
3for number in Numbers:
4    if number > higest_number:
5        higest_number = number

1def return_largest_element(array):
2    largest = 0
3    for x in range(0, len(array)):
4        if(array[x] > largest):
5            largest = array[x]
6    return largest

1mylist = [1, 7, 3, 12, 5]
2
3min_value = min(mylist)
4max_value = max(mylist)
5

1l=[]
2n=int(input("enter the upper limit"))
3for i in range(0,n):
4  a=int(input("enter the numbers"))
5  l.append(a)
6maxno=l[0]
7i=0
8while i<n:
9    if l[i]>maxno:
10        a=l[i]
11        i=i+1
12    elif l[i]>maxno:
13        b=l[i]
14        i=i+1
15        print("max no is :",b)
16        break
17    else:
18        print("max no is",a)
19        break
20#without using function i am just a beginner
21#need improvement to shorten the code but plz without any function 

1n = int(input("Enter number of elements : "))
2l = []
3new=[]
4dope = 0
5for i in range(n):
6    l.append(int(input("Enter a number: ")))
7print(l)
8for i in l :
9    first = i
10    count=0
11    for x in l:
12        if x == first:
13            count+=1
14
15    new.append(count)
16k=new[0]
17print(new)
18for i in new:
19
20    if i >=k:
21        dope = l[i]
22
23
24
25print(dope)
26
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