how to check if a number is odd python

1# Python program to check if the input number is odd or even.
2# A number is even if division by 2 gives a remainder of 0.
3# If the remainder is 1, it is an odd number.
4
5num = int(input("Enter a number: "))
6if (num % 2) == 0:
7   print("{0} is Even".format(num))
8else:
9   print("{0} is Odd".format(num))

1m = int(input("Enter number"))
2if m % 2 == 0:
3    print(m,"is an even number")
4else:
5    print(m,"is an odd number")
6
7    

1num = int(input("Enter a number: "))  
2if (num % 2) == 0:  
3   print("{0} is Even number".format(num))  
4else:  
5   print("{0} is Odd number".format(num))  

1num = int(input("Enter a number: "))
2if (num % 2) == 0:
3   print("{0} is Even".format(num))
4else:
5   print("{0} is Odd".format(num))
6