get next iterator without incrementing python
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showing results for - "get next iterator without incrementing python"
Jonas
27 Jan 2017
1from more_itertools import peekable
2
3p = peekable(['a', 'b'])
4p.peek()
5# 'a'
6next(p)
7# 'a'
8p.peek()
9# 'b'similar questions
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