get largest no in the array javascript

1
2//For Values
3var arr =[1,10,3]
4var min = Math.min.apply(null, arr),
5    max = Math.max.apply(null, arr);
6
7//For Objects
8var arr = [{a: 1},{a: 10},{a: 3}]
9var values = arr.map(val => val.a);
10var max = Math.max.apply(null, values);
11console.log(max)
12

1var peopleData = [ 
2    { name: "Paul", height: 180, age: 21 },
3    { name: "Johnny", height: 198, age: 43 },
4    { name: "Brad", height: 172, age: 49 },
5    { name: "Dwayne", height: 166, age: 15 }
6];
7
8//Find biggest height number
9var maxHeight = 0;
10
11for (var i = 0; i < heights.length; i++) {
12    if (peopleData[i].height > maxHeight) {
13        maxHeight = peopleData[i].height;
14      //if you console.log(maxHeight); you should get 198
15    }
16}

1function maisBaratosQue(valor, precos) {
2   return precos.filter(p => p <= valor);
3}

1//For Values
2var arr =[1,10,3]
3var min = Math.min.apply(null, arr),
4    max = Math.max.apply(null, arr);
5
6//For Objects
7var arr = [{a: 1},{a: 10},{a: 3}]
8var values = arr.map(val => val.a);
9var max = Math.max.apply(null, values);
10console.log(max)

1
2function nthlargest(arra,highest){
3			var x = 0,
4				y = 0,
5				z = 0,
6				temp = 0,
7				tnum = arra.length, 
8				flag = false, 
9				result = false; 
10   
11			while(x < tnum){
12				y = x + 1; 
13				
14				if(y < tnum){
15					for(z = y; z < tnum; z++){
16						
17						if(arra[x] < arra[z]){
18							temp = arra[z];
19							arra[z] = arra[x];
20							arra[x] = temp;
21							flag = true; 
22						}else{
23							continue;
24						}	
25					}					
26				}
27				
28				if(flag){
29					flag = false;
30				}else{
31					x++; 
32					if(x === highest){ 
33                      
34						result = true;
35					}	
36				}
37				if(result){
38					break;
39				}
40			}
41
42			return (arra[(highest - 1)]);	
43		}
44		
45console.log(nthlargest([ 43, 56, 23, 89, 88, 90, 99, 652], 4)); 
46
47

1//get min/max value of arrays
2function getArrayMax(array){
3   return Math.max.apply(null, array);