get current file name python

1import os
2os.path.dirname(os.path.abspath(__file__))

1from pathlib import Path
2print(Path(__file__).stem) #myfile
3print(Path(__file__).name) #myfile.py

1# Option 1: Works for Python 3.4 +
2from pathlib import Path
3Path(__file__).name		# ScriptName.py
4Path(__file__).stem		# ScriptName
5
6# Option 2: use `os` library 
7import os
8os.path.basename(__file__)							# ScriptName.py
9os.path.splitext(os.path.basename(__file__))[0]		# ScriptName

1import os
2
3os.path.basename(__file__)

1import os
2os.path.basename(__file__)

1Use __file__. If you want to omit the directory part (which might be present), you can use os.path.basename(__file__)