find max value in array c 2b 2b

1    int a = 1;
2    int b = 2;
3    int c = 3;
4
5    int m = std::max({a, b, c});

1#include<iostream>
2
3using namespace std;
4
5public void getMax_MinValue(int arr[])
6{
7    int max, min;
8
9    max = arr[0];
10    min = arr[0];
11    for (int i = 0; i < sizeof(arr); i++)
12    {
13        if (max < arr[i])
14            max = arr[i];
15        else if (min > arr[i])
16            min = arr[i];
17    }
18
19    cout << "Largest element : " << max;
20    cout << "Smallest element : " << min;
21 
22}

1cout << " max element is: " << *max_element(array , array + n) << endl;

1*max_element (first_index, last_index);
2ex:- for an array arr of size n
3*max_element(arr, arr + n);

1#include <iostream>
2using namespace std;
3int main(){
4   //n is the number of elements in the array
5   int n, largest;
6   int num[50];
7   cout<<"Enter number of elements you want to enter: ";
8   cin>>n;
9   
10   /* Loop runs from o to n, in such a way that first
11    * element entered by user is stored in num[0], second 
12    * in num[1] and so on. 
13    */
14   for(int i = 0; i < n; i++) {
15      cout<<"Enter Element "<<(i+1)<< ": ";
16      cin>>num[i];
17   }
18   // Storing first array element in "largest" variable
19   largest = num[0];
20   for(int i = 1;i < n; i++) {
21      /* We are comparing largest variable with every element
22       * of array. If there is an element which is greater than
23       * largest variable value then we are copying that variable
24       * to largest, this way we have the largest element copied
25       * to the variable named "largest" at the end of the loop 
26       *
27       */
28      if(largest < num[i])
29         largest = num[i];
30   } 
31   cout<<"Largest element in array is: "<<largest;
32   return 0;
33}

1---without sort method---
2public static int maxValue( int[]  n ) {
3
4int max = Integer.MIN_VALUE;
5
6for(int each: n)
7
8if(each > max)
9
10max = each;
11
12 
13return max;
14  
15---with sort method---
16public static int maxValue( int[]  n ) {
17
18Arrays.sort( n );
19
20return  n [ n.lenth-1 ];
21
22}